Create tanyatandon.txt

Tanya Tandon/linux assignment.txt

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+Assignment - 1
+Q-1 when we create a user ,some hidden files are genrated in the directory of the same user at that time . how is it done ?
+A-1 ls -a cmd use for to see the hidden file in linux
+      . / .. it is show that folders are hidden or not.
+Q-2 make subdirectories inside a parent directory by using single mkdir command .
+A- mkdir a/b/v
+
+Q-3 tac & cat cmd
+A- The word tac is reverse of the word cat. 
+    The tac command functionality is also reverse of the cat command. 
+    cat command prints the file. tac command prints the file in reverse order with the last line first
+
+
+Assignment - 2
+q-1 Chnge the Umask value for any user permanently.
+A. man -k umask 
+    sudo gedit /etc/login.defs
+chng umask value 
+    if usergroups_enab = yes , chnage into no
+then change the umask value
+
+Q-2 addd a new user without using adduser & useradd cmd
+A- add a new user
+     #vim /etc/passwd
+     then press insert key and add user
+
+Q-3 can we change the umask value to 0888.
+A- No, we can't change the umask value to 0888.
+     highest value is 0777
+     -rwx have h 777 value
+
+Q-4 how to add a new user with a unique user id &check out the unique id of that user.
+A- #useradd jass
+    #usermod jass
+    #id jass
+    #sudo usermod -u 1345 jass
+
+Q-5 how to change the group of any folder.
+A- 1) 
+      In kali we can't change the root.
+      In other o.s. we chnage folder
+    2)
+      #chgrp jass file.txt
+        go to jass then #ll to see jass group is make or not.
+
+
+
+Assignment -3 
+Q-1 create & compress the file with bzip2
+A- #bzip2 jass
+    #bunzip2 jass
+
+Q-2 what should be the argument to be given to unzip that file .
+A- #gzip jass
+    #gunzip jass
+    #unzip jass
+
+Q-3 read a file & show the data on terminal using file input & output redirection.
+A- #cat < jass > file.txt
+
+Q-4 how to change the shell of user to "/bin/sh" at the time of adding the user.
+A- firstly check the type of shell 
+    #sudo cat /etc/shells
+    #/etc/shells
+       aftr
+    #sudo chsh -s /bin/bash jass 
+      jass is new usr
+    #sudo nano /etc/passwd

Tanya Tandon/pyth.py

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+#Python Class 3:
+#1)Find the Armstrong Number between the two numbers which are input by user
+#Armstrong number : 153 -> 1*1*1 + 5*5*5 + 3*3*3
+#ans
+num = int(input("Enter a number: "))
+sum = 0
+temp = num
+while temp > 0:
+   digit = temp % 10
+   sum += digit ** 3
+   temp //= 10
+if num == sum:
+    print(num,"is an Armstrong number")
+else:
+    print(num,"is not an Armstrong number")
+
+#2Let’s say you have a string “hello this world @2020!!! ”
+#Remove the punctuation like [“@!#$%&*()”] from the string
+# Final output should be without the punctuation
+# “hello this world 2020”
+
+#ans
+punctuations = '''!()-[]{};:'"\,<>./?@#$%^&*_~'''
+my_str = 'hello this world @2020!!!'
+no_punct = ""
+for char in my_str:
+    if char not in punctuations:
+        no_punct = no_punct + char
+print(no_punct)
+
+# You have a list with words - [“Apple”, “banana”, “cat”, “REGEX”,”apple”]
+# Sort words in Alphabetical order
+#If you get output, like [Apple, apple, banana]
+# How has it happened?
+o =['Apple', 'banana', 'cat', 'REGEX','apple']
+o.sort()
+print(o)

Tanya Tandon/python assignment.txt

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+python class 1
+1)what is jpython and cpython?
+ans.-cypthon is both the compiler as well as the interpreter. it will convert the written python code into the byte code before interpreting it.
+it is the default and most widely used implementation of the language.
+jpython-it is the implementation of python working on the java platform.
+
+2) basic difference between pyhton2 and pyhton3.
+ans.- in python2 it takes the user input and default storing os string is in the ASCII code.whereas in python3 we take only input and default storing of string is in unicode.
+
+3)difference between ASCII Code and unicode.
+ans-
+Unicode and ASCII both are standards for encoding texts
+ASCII CODE-ASCII is a character-encoding scheme and it was the first character encoding standard.ASCII uses 7 bits to represent a character. It has 128 code points, 0 through 127.  It is a code for representing English characters as numbers, with each letter assigned a number from 0 to 127.
+
+UNICODE-Unicode is a universal international standard character encoding that is capable of representing most of the world's written languages. It assigns each character a unique number, or code point. 
+
+
+1) what will be the output of 3+4**6-9*10/2
+ans- exponent>multiplication=division>addition=subtraction
+=3+4**6-9*5
+=3+4096-45
+=4099-45=4054
+so by this  the answer will be 4054.
+
+2)lets say i have a string "hello this side regex". count the total no. of vowels present in the  string.
+ans-
+string=input("Enter string:")
+vowels=0
+for i in string:
+      if(i=='a' or i=='e' or i=='i' or i=='o' or i=='u' or i=='A' or i=='E' or i=='I' or i=='O' or i=='U'):
+      vowels=vowels+1
+print("Number of vowels are:",vowel)
+
+3)find out the area of the triangle . you have to take the value from the user about the base and the height.
+ans-
+h=int(input("enter the height of the triangle=))
+b=int(input("enter the base of the triangle=))
+print("area of the traingle is=",(1/2)*b*h)

Tanya Tandon/python2.py

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+#1 what will be the output of 3+4**6-9*10/2
+#ans- exponent>multiplication=division>addition=subtraction
+#=3+4**6-9*5
+#=3+4096-45
+#=4099-45=4054
+#so by this  the answer will be 4054.
+print(3+4**6-9*10/2)
+
+
+#2)lets say i have a string "hello this side regex". count the total no. of vowels present in the  string.
+#ans-
+string=input("Enter string:")
+vowels=0
+for i in string:
+    if(i=='a' or i=='e' or i=='i' or i=='o' or i=='u' or i=='A' or i=='E' or i=='I' or i=='O' or i=='U'):
+        vowels=vowels+1
+print("Number of vowels are:",vowels)
+
+
+#3)find out the area of the triangle . you have to take the value from the user about the base and the height.
+#ans-
+h=int(input("enter the height of the triangle="))
+b=int(input("enter the base of the triangle="))
+print("area of the traingle is=",(1/2)*b*h)

Tanya Tandon/python3.py

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+#Python Class 3:
+#1)Find the Armstrong Number between the two numbers which are input by user
+#Armstrong number : 153 -> 1*1*1 + 5*5*5 + 3*3*3
+#ans
+num = int(input("Enter a number: "))
+sum = 0
+temp = num
+while temp > 0:
+   digit = temp % 10
+   sum += digit ** 3
+   temp //= 10
+if num == sum:
+    print(num,"is an Armstrong number")
+else:
+    print(num,"is not an Armstrong number")
+
+#2Let’s say you have a string “hello this world @2020!!! ”
+#Remove the punctuation like [“@!#$%&*()”] from the string
+# Final output should be without the punctuation
+# “hello this world 2020”
+
+#ans
+punctuations = '''!()-[]{};:'"\,<>./?@#$%^&*_~'''
+my_str = 'hello this world @2020!!!'
+no_punct = ""
+for char in my_str:
+    if char not in punctuations:
+        no_punct = no_punct + char
+print(no_punct)
+
+# You have a list with words - [“Apple”, “banana”, “cat”, “REGEX”,”apple”]
+# Sort words in Alphabetical order
+#If you get output, like [Apple, apple, banana]
+# How has it happened?
+o =['Apple', 'banana', 'cat', 'REGEX','apple']
+o.sort()
+print(o)

Tanya Tandon/python4.py

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+#1)Write a Program to print new list which contains all the first Characters of strings present in a List.
+#LIST_STATES = ["GOA","RAJASTHAN","KARNATAKA","GUJRAT","MANIPUR", “MADHYA PRADESH”]
+#Sol.
+LIST_STATES = ["GOA","RAJASTHAN","KARNATAKA","GUJRAT","MANIPUR", "MADHYA PRADESH"]
+for i in LIST_STATES:
+    print(i[0])
+
+
+#2)Write a program to replace each string with an integer value in a given list of strings. The replacement integer value should be a sum of AScci values of each character of type corresponding string.
+#LIST: ['GAnga', 'Tapti', 'Kaveri', 'Yamuna', 'Narmada' ]
+#Sol.
+LIST=['GAnga', 'Tapti', 'Kaveri', 'Yamuna', 'Narmada' ]
+k=0
+for i in LIST:
+    j=0
+    sum_=0
+    for j in i:
+        sum_=sum_ + ord(j)
+    LIST[k]=sum_
+    k+=1
+print(LIST)
+
+
+#3)You have to run your Program at 9:00am. Date: 14th April 2020.
+#HINT:
+# You have to use datetime Module or time module..
+# You have to convert your output in #LIST_FORMAT
+# [ '2020-04-13' , '17:11:01.952975' ]
+# you can use this with the helf of IF/Else statement
+#sol)
+
+
+#4)GIve a tuple:tuple = ('a','l','g','o','r','i','t','h','m')
+#1. Using the concept of slicing, print the whole tuple
+#2. delete the element at the 3rd Index, print the tuple.
+tuple = ('a','l','g','o','r','i','t','h','m')
+print(tuple[0:])
+
+tuple = tuple[:2] + tuple[3:]
+print(tuple)
+
+#5. Take a list REGex=[1,2,3,4,5,6,7,8,9,0,77,44,15,33,65,89,12]
+#- print only those numbers greator then 20
+#- then print those numbers those are less then 10 or equal to 10
+#- store these above two list in two different list.
+#Sol.
+REGex=[1,2,3,4,5,6,7,8,9,0,77,44,15,33,65,89,12]
+list1=[]
+list2=[]
+for i in REGex:
+    if i> 20:
+        list1.append(i)
+    if i<= 10:
+        list2.append(i)  
+print(list1)
+print(list2)
+
+#6. Execute standard LINUX Commands using Python Programming
+#Sol.
+import os
+cmd = 'wc -l my_text_file.txt > out_file.txt'
+os.system(cmd)
+
+#7. Revise *args and **kwargs Concepts
+#Sol.
+def totalSum(*args):
+    result = 0
+    for x in args:
+        result += x
+    return result
+
+def concStr(**kwargs):
+    result = ""
+    for arg in kwargs.values():
+        result += arg
+    return result
+
+print(totalSum(1, 2, 3))
+print(concStr(a="This", b="is", c="a", d="Python", e="Program"))

tanya tandon/LINUX ASSIGNMENTS/linux assignment.txt

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+linux assignment 
+Assignment - 1
+Q-1 when we create a user ,some hidden files are genrated in the directory of the same user at that time . how is it done ?
+A-1 ls -a cmd use for to see the hidden file in linux
+      . / .. it is show that folders are hidden or not.
+Q-2 make subdirectories inside a parent directory by using single mkdir command .
+A- mkdir a/b/v
+
+Q-3 tac & cat cmd
+A- The word tac is reverse of the word cat. 
+    The tac command functionality is also reverse of the cat command. 
+    cat command prints the file. tac command prints the file in reverse order with the last line first
+
+
+Assignment - 2
+q-1 Change the Umask value for any user permanently.
+A. man -k umask 
+    sudo gedit /etc/login.defs
+chng umask value 
+    if usergroups_enab = yes , change into no
+then change the umask value
+
+Q-2 addd a new user without using adduser & useradd cmd
+A- add a new user
+     #vim /etc/passwd
+     then press insert key and add user
+
+Q-3 can we change the umask value to 0888.
+A- No, we can't change the umask value to 0888.
+     highest value is 0777
+     -rwx have h 777 value
+
+Q-4 how to add a new user with a unique user id &check out the unique id of that user.
+A- #useradd jass
+    #usermod jass
+    #id jass
+    #sudo usermod -u 1345 jass
+
+Q-5 how to change the group of any folder.
+A- 1) 
+      In kali we can't change the root.
+      In other o.s. we can change the folder
+    2)
+      #chgrp jass file.txt
+        go to jass then #ll to see jass group is make or not.
+
+
+
+Assignment -3 
+Q-1 create & compress the file with bzip2
+A- #bzip2 jass
+    #bunzip2 jass
+
+Q-2 what should be the argument to be given to unzip that file .
+A- #gzip jass
+    #gunzip jass
+    #unzip jass
+
+Q-3 read a file & show the data on terminal using file input & output redirection.
+A- #cat < jass > file.txt
+
+Q-4 how to change the shell of user to "/bin/sh" at the time of adding the user.
+A- firstly check the type of shell 
+    #sudo cat /etc/shells
+    #/etc/shells
+       aftr
+    #sudo chsh -s /bin/bash jass 
+      jass is new usr
+    #sudo nano /etc/passwd