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@dnagel21 dnagel21 commented Sep 4, 2017

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@json-derulo json-derulo left a comment

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Format the code indentations properly

Matcher m = Pattern.compile(Regex.GETMETHODHEADERPARAMETER).matcher(paramUnformatted);
while (m.find() && isDefaultValue) {
List<String> paramUnformattedTest = new ArrayList<String>();
paramUnformattedTest.add(m.group());
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@json-derulo json-derulo Sep 4, 2017

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Die Liste paramUnformattedTest enthält höchstens einen Wert. Du kannst mit dem String direkt arbeiten.

paramUnformattedTest.add(m.group());
for (int i = 0; i < paramUnformattedTest.size(); i++) {
if (paramUnformattedTest.get(i).contains("@DefaultValue")) {
createMapFromParameters(paramUnformatted);
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Die Methode gibt eine Map zurück, der Rückgabewert wird aber nie verwendet.


String param = paramUnformatted.replaceAll("[\\s]*" + Regex.ANNOTATION + "[\\s]*", "").trim();

List<String> defaultValue = new ArrayList<String>();
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Namensgebung: Damit man direkt sehen kann, dass es mehrere Werte sind, lieber umbenennen zu defaultValues

if (isDefaultValue) {
parameter.setLocation("query");
// parameter.setType(type);
for (int i = 0; i < defaultValue.size(); i++) {
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Ich bevorzuge for-Schleifen mit der Doppelpunkt-Schreibweise
for (String value: defaultValue) { }

parameter.setLocation("query");
// parameter.setType(type);
for (int i = 0; i < defaultValue.size(); i++) {
parameter.setDefaultValue(defaultValue.get(i));
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Aktuell ist es so, wenn es mehrere defaultValues gibt, wird nur das letzte genommen.
Kann es überhaupt mehrere geben?

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improvements and best practices

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