fix: Encapsulates subscription steam consumption

README.md

@@ -58,8 +58,8 @@ The result of this query is a `GraphQLResult` that encodes to the following JSON
 ### Subscription
 
 This package supports GraphQL subscription. To create a subscription field in a GraphQL schema, use the `subscribe`
-resolver that returns any type that conforms to `AsyncSequence`. You must also provide a `resolver`, which defines how
-to process each event as it occurs and must return the field result type. Here is an example:
+resolver that returns any type that conforms to `AsyncSequence`, with a `Sendable` element type. You must also provide
+a `resolver`, which defines how to process each event as it occurs and must return the field result type. Here is an example:
 
 ```swift
 let schema = try GraphQLSchema(

Sources/GraphQL/Subscription/Subscribe.swift

@@ -32,25 +32,37 @@ func subscribe(
     )
 
     return sourceResult.map { sourceStream in
-        AsyncThrowingStream<GraphQLResult, Error> {
-            // The type-cast below is required on Swift <6. Once we drop Swift 5 support it may be
-            // removed.
-            var iterator = sourceStream.makeAsyncIterator() as (any AsyncIteratorProtocol)
-            guard let eventPayload = try await iterator.next() else {
-                return nil
+        AsyncThrowingStream<GraphQLResult, Error> { continuation in
+            let task = Task {
+                do {
+                    for try await event in sourceStream {
+                        // Check for cancellation before processing each event
+                        try Task.checkCancellation()
+
+                        let result = try await execute(
+                            schema: schema,
+                            documentAST: documentAST,
+                            // Despite the warning, we must force unwrap because on optional unwrap,
+                            // compiler throws:
+                            // `marker protocol 'Sendable' cannot be used in a conditional cast`
+                            rootValue: event as! (any Sendable),
+                            context: context,
+                            variableValues: variableValues,
+                            operationName: operationName
+                        )
+                        continuation.yield(result)
+                    }
+                    continuation.finish()
+                } catch is CancellationError {
+                    continuation.finish()
+                } catch {
+                    continuation.finish(throwing: error)
+                }
+            }
+
+            continuation.onTermination = { @Sendable _ in
+                task.cancel()
             }
-            // Despite the warning, we must force unwrap because on optional unwrap, compiler
-            // throws:
-            // `marker protocol 'Sendable' cannot be used in a conditional cast`
-            let rootValue = eventPayload as! (any Sendable)
-            return try await execute(
-                schema: schema,
-                documentAST: documentAST,
-                rootValue: rootValue,
-                context: context,
-                variableValues: variableValues,
-                operationName: operationName
-            )
         }
     }
 }
@@ -206,8 +218,9 @@ func executeSubscription(
     } else if let error = resolved as? GraphQLError {
         return .failure(.init([error]))
     } else if let stream = resolved as? any AsyncSequence {
-        // Despite the warning, we must force unwrap because on optional unwrap, compiler throws:
-        // `marker protocol 'Sendable' cannot be used in a conditional cast`
+        // Force cast is required because Swift doesn't allow conditional casting with marker
+        // protocols like Sendable. This is safe because subscription resolvers should only
+        // return Sendable AsyncSequences.
         return .success(stream as! (any AsyncSequence & Sendable))
     } else if resolved == nil {
         return .failure(.init([