Create 2127. Maximum Employees to Be Invited to a Meeting

2127. Maximum Employees to Be Invited to a Meeting

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+class Solution {
+public:
+    int maximumInvitations(vector<int>& favorite) {
+
+        int n = favorite.size();
+        vector<int> indegree(n, 0);
+        vector<int> chain(n, 0);
+        vector<bool> vis(n, false);
+        for (int i : favorite) {
+            indegree[i]++;
+        }
+        queue<int> q;
+        for (int i = 0; i < n; i++) {
+            if (!indegree[i]) {
+                q.push(i);
+            }
+        }
+        while (!q.empty()) {
+            int front = q.front();
+            q.pop();
+            vis[front] = true;
+            int next = favorite[front];
+            chain[next] = chain[front] + 1;
+            if (--indegree[next] == 0) {
+                q.push(next);
+            }
+        }
+
+        int maxCycle = 0, total = 0;
+        for (int i = 0; i < n; i++) {
+            if (!vis[i]) {
+                int c = i, len = 0;
+                while (!vis[c]) {
+                    vis[c] = true;
+                    c = favorite[c];
+                    len++;
+                }
+                if (len == 2) {
+                    total += (2 + chain[i] + chain[favorite[i]]);
+                } else {
+                    maxCycle = max(maxCycle, len);
+                }
+            }
+        }
+        return max(total, maxCycle);
+
+    }
+};