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Original file line number Diff line number Diff line change
@@ -0,0 +1,49 @@
# [2528.Maximize the Minimum Powered City][title]

## Description
You are given a **0-indexed** integer array `stations` of length `n`, where `stations[i]` represents the number of power stations in the `ith` city.

Each power station can provide power to every city in a fixed **range**. In other words, if the range is denoted by r, then a power station at city `i` can provide power to all cities `j` such that `|i - j| <= r` and `0 <= i, j <= n - 1`.

- Note that `|x|` denotes absolute value. For example, `|7 - 5| = 2` and `|3 - 10| = 7`.

The **power** of a city is the total number of power stations it is being provided power from.

The government has sanctioned building `k` more power stations, each of which can be built in any city, and have the same range as the pre-existing ones.

Given the two integers `r` and `k`, return the **maximum possible minimum power** of a city, if the additional power stations are built optimally.

**Note** that you can build the k power stations in multiple cities.

**Example 1:**

```
Input: stations = [1,2,4,5,0], r = 1, k = 2
Output: 5
Explanation:
One of the optimal ways is to install both the power stations at city 1.
So stations will become [1,4,4,5,0].
- City 0 is provided by 1 + 4 = 5 power stations.
- City 1 is provided by 1 + 4 + 4 = 9 power stations.
- City 2 is provided by 4 + 4 + 5 = 13 power stations.
- City 3 is provided by 5 + 4 = 9 power stations.
- City 4 is provided by 5 + 0 = 5 power stations.
So the minimum power of a city is 5.
Since it is not possible to obtain a larger power, we return 5.
```

**Example 2:**

```
Input: stations = [4,4,4,4], r = 0, k = 3
Output: 4
Explanation:
It can be proved that we cannot make the minimum power of a city greater than 4.
```

## 结语

如果你同我一样热爱数据结构、算法、LeetCode,可以关注我 GitHub 上的 LeetCode 题解:[awesome-golang-algorithm][me]

[title]: https://leetcode.com/problems/maximize-the-minimum-powered-city
[me]: https://github.com/kylesliu/awesome-golang-algorithm
Original file line number Diff line number Diff line change
@@ -1,5 +1,59 @@
package Solution

func Solution(x bool) bool {
return x
func Solution(stations []int, r int, k int) int64 {
n := len(stations)
cnt := make([]int64, n+1)
for i := 0; i < n; i++ {
left := max(0, i-r)
right := min(n, i+r+1)
cnt[left] += int64(stations[i])
cnt[right] -= int64(stations[i])
}

minVal := int64(stations[0])
sumTotal := int64(0)
for _, s := range stations {
if int64(s) < minVal {
minVal = int64(s)
}
sumTotal += int64(s)
}

lo, hi := minVal, sumTotal+int64(k)
var res int64 = 0

for lo <= hi {
mid := lo + (hi-lo)/2
if check(cnt, mid, r, k) {
res = mid
lo = mid + 1
} else {
hi = mid - 1
}
}
return res
}

func check(cnt []int64, val int64, r int, k int) bool {
n := len(cnt) - 1
diff := make([]int64, len(cnt))
copy(diff, cnt)
var sum int64 = 0
remaining := int64(k)

for i := 0; i < n; i++ {
sum += diff[i]
if sum < val {
add := val - sum
if remaining < add {
return false
}
remaining -= add
end := min(n, i+2*r+1)
diff[end] -= add
sum += add
}
}

return true
}
Original file line number Diff line number Diff line change
Expand Up @@ -9,31 +9,31 @@ import (
func TestSolution(t *testing.T) {
// 测试用例
cases := []struct {
name string
inputs bool
expect bool
name string
stations []int
r, k int
expect int64
}{
{"TestCase", true, true},
{"TestCase", true, true},
{"TestCase", false, false},
{"TestCase1", []int{1, 2, 4, 5, 0}, 1, 2, 5},
{"TestCase2", []int{4, 4, 4, 4}, 0, 3, 4},
}

// 开始测试
for i, c := range cases {
t.Run(c.name+" "+strconv.Itoa(i), func(t *testing.T) {
got := Solution(c.inputs)
got := Solution(c.stations, c.r, c.k)
if !reflect.DeepEqual(got, c.expect) {
t.Fatalf("expected: %v, but got: %v, with inputs: %v",
c.expect, got, c.inputs)
t.Fatalf("expected: %v, but got: %v, with inputs: %v %v %v",
c.expect, got, c.stations, c.r, c.k)
}
})
}
}

// 压力测试
// 压力测试
func BenchmarkSolution(b *testing.B) {
}

// 使用案列
// 使用案列
func ExampleSolution() {
}
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