@@ -379,7 +379,6 @@ static bool unifyConcreteTypes(
379379// / When a type parameter has two superclasses, we have to both unify the
380380// / type constructor arguments, and record the most derived superclass.
381381// /
382- // /
383382// / For example, if we have this setup:
384383// /
385384// / class Base<T, T> {}
@@ -544,7 +543,7 @@ PropertyMap::~PropertyMap() {
544543 clear ();
545544}
546545
547- // / Look for an property bag corresponding to a suffix of the given key.
546+ // / Look for a property bag corresponding to a suffix of the given key.
548547// /
549548// / Returns nullptr if no information is known about this key.
550549PropertyBag *
@@ -555,7 +554,7 @@ PropertyMap::lookUpProperties(const MutableTerm &key) const {
555554 return nullptr ;
556555}
557556
558- // / Look for an property bag corresponding to the given key, creating a new
557+ // / Look for a property bag corresponding to the given key, creating a new
559558// / property bag if necessary.
560559// /
561560// / This must be called in monotonically non-decreasing key order.
@@ -567,7 +566,7 @@ PropertyMap::getOrCreateProperties(Term key) {
567566
568567 auto *props = new PropertyBag (key);
569568
570- // Look for the longest suffix of the key that has an property bag,
569+ // Look for the longest suffix of the key that has a property bag,
571570 // recording it as the next property bag if we find one.
572571 //
573572 // For example, if our rewrite system contains the following three rules:
@@ -841,7 +840,7 @@ void PropertyMap::concretizeNestedTypesFromConcreteParent(
841840 }
842841}
843842
844- // / Given the key of an property bag known to have \p concreteType,
843+ // / Given the key of a property bag known to have \p concreteType,
845844// / together with a \p typeWitness from a conformance on that concrete
846845// / type, return the right hand side of a rewrite rule to relate
847846// / \p subjectType with a term representing the type witness.
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