Sync LeetCode submission Runtime - 703 ms (85.71%), Memory - 18.3 MB (32.24%)

Author: jimit105

0322-coin-change/README.md

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+<p>You are given an integer array <code>coins</code> representing coins of different denominations and an integer <code>amount</code> representing a total amount of money.</p>
+
+<p>Return <em>the fewest number of coins that you need to make up that amount</em>. If that amount of money cannot be made up by any combination of the coins, return <code>-1</code>.</p>
+
+<p>You may assume that you have an infinite number of each kind of coin.</p>
+
+<p>&nbsp;</p>
+<p><strong class="example">Example 1:</strong></p>
+
+<pre>
+<strong>Input:</strong> coins = [1,2,5], amount = 11
+<strong>Output:</strong> 3
+<strong>Explanation:</strong> 11 = 5 + 5 + 1
+</pre>
+
+<p><strong class="example">Example 2:</strong></p>
+
+<pre>
+<strong>Input:</strong> coins = [2], amount = 3
+<strong>Output:</strong> -1
+</pre>
+
+<p><strong class="example">Example 3:</strong></p>
+
+<pre>
+<strong>Input:</strong> coins = [1], amount = 0
+<strong>Output:</strong> 0
+</pre>
+
+<p>&nbsp;</p>
+<p><strong>Constraints:</strong></p>
+
+<ul>
+	<li><code>1 &lt;= coins.length &lt;= 12</code></li>
+	<li><code>1 &lt;= coins[i] &lt;= 2<sup>31</sup> - 1</code></li>
+	<li><code>0 &lt;= amount &lt;= 10<sup>4</sup></code></li>
+</ul>

0322-coin-change/solution.py

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+# Approach 3: (Dynamic programming - Bottom up)
+
+# S = amount
+# Time: O(S * n)
+# Space: O(S)
+
+class Solution:
+    def coinChange(self, coins: List[int], amount: int) -> int:
+        dp = [float('inf')] * (amount + 1)
+        dp[0] = 0
+
+        for coin in coins:
+            for x in range(coin, amount + 1):
+                dp[x] = min(dp[x], dp[x - coin] + 1)
+
+        return dp[amount] if dp[amount] != float('inf') else -1
+