Sync LeetCode submission Runtime - 0 ms (100.00%), Memory - 17.9 MB (26.17%)

Author: jimit105

1411-convert-binary-number-in-a-linked-list-to-integer/README.md

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+<p>Given <code>head</code> which is a reference node to a singly-linked list. The value of each node in the linked list is either <code>0</code> or <code>1</code>. The linked list holds the binary representation of a number.</p>
+
+<p>Return the <em>decimal value</em> of the number in the linked list.</p>
+
+<p>The <strong>most significant bit</strong> is at the head of the linked list.</p>
+
+<p>&nbsp;</p>
+<p><strong class="example">Example 1:</strong></p>
+<img alt="" src="https://assets.leetcode.com/uploads/2019/12/05/graph-1.png" style="width: 426px; height: 108px;" />
+<pre>
+<strong>Input:</strong> head = [1,0,1]
+<strong>Output:</strong> 5
+<strong>Explanation:</strong> (101) in base 2 = (5) in base 10
+</pre>
+
+<p><strong class="example">Example 2:</strong></p>
+
+<pre>
+<strong>Input:</strong> head = [0]
+<strong>Output:</strong> 0
+</pre>
+
+<p>&nbsp;</p>
+<p><strong>Constraints:</strong></p>
+
+<ul>
+	<li>The Linked List is not empty.</li>
+	<li>Number of nodes will not exceed <code>30</code>.</li>
+	<li>Each node&#39;s value is either <code>0</code> or <code>1</code>.</li>
+</ul>

1411-convert-binary-number-in-a-linked-list-to-integer/solution.py

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+# Approach 2: Bit Manipulation
+
+# Time: O(n)
+# Space: O(1)
+
+# Definition for singly-linked list.
+# class ListNode:
+#     def __init__(self, val=0, next=None):
+#         self.val = val
+#         self.next = next
+class Solution:
+    def getDecimalValue(self, head: Optional[ListNode]) -> int:
+        num = head.val
+        while head.next:
+            num = (num << 1) | head.next.val
+            head = head.next
+
+        return num