Improved task 2070.

Author: javadev

src/main/java/g2001_2100/s2070_most_beautiful_item_for_each_query/readme.md

@@ -14,17 +14,19 @@ Return _an array_ `answer` _of the same length as_ `queries` _where_ `answer[j]`
 
 **Output:** [2,4,5,5,6,6]
 
-**Explanation:** -
+**Explanation:**
 
-For queries[0]=1, [1,2] is the only item which has price <= 1. Hence, the answer for this query is 2.
+- For queries[0]=1, [1,2] is the only item which has price <= 1. Hence, the answer for this query is 2.
 
-- For queries[1]=2, the items which can be considered are [1,2] and [2,4]. 
+- For queries[1]=2, the items which can be considered are [1,2] and [2,4].
 
-The maximum beauty among them is 4. 
-- For queries[2]=3 and queries[3]=4, the items which can be considered are [1,2], [3,2], [2,4], and [3,5]. 
+The maximum beauty among them is 4.
 
-The maximum beauty among them is 5. 
-- For queries[4]=5 and queries[5]=6, all items can be considered. 
+- For queries[2]=3 and queries[3]=4, the items which can be considered are [1,2], [3,2], [2,4], and [3,5].
+
+The maximum beauty among them is 5.
+
+- For queries[4]=5 and queries[5]=6, all items can be considered.
 
 Hence, the answer for them is the maximum beauty of all items, i.e., 6. 
 
@@ -34,7 +36,9 @@ Hence, the answer for them is the maximum beauty of all items, i.e., 6.
 
 **Output:** [4]
 
-**Explanation:** The price of every item is equal to 1, so we choose the item with the maximum beauty 4. 
+**Explanation:**
+
+The price of every item is equal to 1, so we choose the item with the maximum beauty 4.
 
 Note that multiple items can have the same price and/or beauty. 
 
@@ -44,12 +48,14 @@ Note that multiple items can have the same price and/or beauty.
 
 **Output:** [0]
 
-**Explanation:** No item has a price less than or equal to 5, so no item can be chosen. 
+**Explanation:**
+
+No item has a price less than or equal to 5, so no item can be chosen.
 
 Hence, the answer to the query is 0. 
 
 **Constraints:**
 
 *   <code>1 <= items.length, queries.length <= 10<sup>5</sup></code>
 *   `items[i].length == 2`
-*   <code>1 <= price<sub>i</sub>, beauty<sub>i</sub>, queries[j] <= 10<sup>9</sup></code>
+*   <code>1 <= price<sub>i</sub>, beauty<sub>i</sub>, queries[j] <= 10<sup>9</sup></code>