Skip to content

Lab | SQL 7 LAB[ANDERSON CASAGRANDE] #35

New issue

Have a question about this project? Sign up for a free GitHub account to open an issue and contact its maintainers and the community.

Sign up for GitHub

By clicking “Sign up for GitHub”, you agree to our terms of service and privacy statement. We’ll occasionally send you account related emails.

Already on GitHub? Sign in to your account

Open
wants to merge 1 commit into
base: master
Choose a base branch
from
Open

Lab | SQL 7 LAB[ANDERSON CASAGRANDE] #35

Changes from all commits
Commits
Show all changes
1 commit
Select commit
File filter

Filter by extension

Filter by extension
Conversations
Failed to load comments.
Loading
Jump to
Jump to file
Failed to load files.
Loading
Diff view
Diff view
34 changes: 34 additions & 0 deletions Lab SQL 7.sql
View file
Open in desktop
Original file line number Diff line number Diff line change
@@ -0,0 +1,34 @@
-- 1. Create a table rentals_may to store the data from rental table with information for the month of May.
CREATE TEMPORARY TABLE SAKILA.MAY_RENTALS AS
SELECT * FROM SAKILA.RENTAL
WHERE MONTH(RENTAL_DATE) = 5;

-- 2. Insert values in the table rentals_may using the table rental, filtering values only for the month of May.
INSERT INTO MAY_RENTALS
SELECT * FROM SAKILA.RENTAL
WHERE MONTH(RENTAL_DATE) = 5;

SELECT * FROM SAKILA.MAY_RENTALS;

-- 3. Create a table rentals_june to store the data from rental table with information for the month of June.
CREATE TEMPORARY TABLE SAKILA.JUNE_RENTALS AS
SELECT * FROM SAKILA.RENTAL
WHERE MONTH(RENTAL_DATE) = 6;

-- 4. Insert values in the table rentals_june using the table rental,
-- filtering values only for the month of June.
INSERT INTO JUNE_RENTALS
SELECT * FROM SAKILA.RENTAL
WHERE MONTH(RENTAL_DATE) = 6;

SELECT * FROM SAKILA.JUNE_RENTALS;

-- 5. Check the number of rentals for each customer for May.
SELECT CUSTOMER_ID, COUNT(*) AS CUSTOMER_MAY_COUNT
FROM SAKILA.MAY_RENTALS
GROUP BY CUSTOMER_ID;

-- 6. Check the number of rentals for each customer for June.
SELECT CUSTOMER_ID, COUNT(*) AS CUSTOMER_JUNE_COUNT
FROM SAKILA.JUNE_RENTALS
GROUP BY CUSTOMER_ID;