find alll

Author: iamAntimPal

2115. Find All Possible Recipes from Given Supplies.py

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+ 
+ """ 
+  2115. Find All Possible Recipes from Given Supplies
+
+You have information about n different recipes. You are given a string array recipes and a 2D string array ingredients. The ith recipe has the name recipes[i], and you can create it if you have all the needed ingredients from ingredients[i]. A recipe can also be an ingredient for other recipes, i.e., ingredients[i] may contain a string that is in recipes.
+
+You are also given a string array supplies containing all the ingredients that you initially have, and you have an infinite supply of all of them.
+
+Return a list of all the recipes that you can create. You may return the answer in any order.
+
+Note that two recipes may contain each other in their ingredients.
+
+ 
+
+Example 1:
+
+Input: recipes = ["bread"], ingredients = [["yeast","flour"]], supplies = ["yeast","flour","corn"]
+Output: ["bread"]
+Explanation:
+We can create "bread" since we have the ingredients "yeast" and "flour".
+Example 2:
+
+Input: recipes = ["bread","sandwich"], ingredients = [["yeast","flour"],["bread","meat"]], supplies = ["yeast","flour","meat"]
+Output: ["bread","sandwich"]
+Explanation:
+We can create "bread" since we have the ingredients "yeast" and "flour".
+We can create "sandwich" since we have the ingredient "meat" and can create the ingredient "bread".
+Example 3:
+
+Input: recipes = ["bread","sandwich","burger"], ingredients = [["yeast","flour"],["bread","meat"],["sandwich","meat","bread"]], supplies = ["yeast","flour","meat"]
+Output: ["bread","sandwich","burger"]
+Explanation:
+We can create "bread" since we have the ingredients "yeast" and "flour".
+We can create "sandwich" since we have the ingredient "meat" and can create the ingredient "bread".
+We can create "burger" since we have the ingredient "meat" and can create the ingredients "bread" and "sandwich".
+ 
+
+Constraints:
+
+n == recipes.length == ingredients.length
+1 <= n <= 100
+1 <= ingredients[i].length, supplies.length <= 100
+1 <= recipes[i].length, ingredients[i][j].length, supplies[k].length <= 10
+recipes[i], ingredients[i][j], and supplies[k] consist only of lowercase English letters.
+All the values of recipes and supplies combined are unique.
+Each ingredients[i] does not contain any duplicate values.
+"""
+
+class Solution:
+    def findAllRecipes(
+        self, recipes: List[str], ingredients: List[List[str]], supplies: List[str]
+    ) -> List[str]:
+        g = defaultdict(list)
+        indeg = defaultdict(int)
+        for a, b in zip(recipes, ingredients):
+            for v in b:
+                g[v].append(a)
+            indeg[a] += len(b)
+        q = supplies
+        ans = []
+        for i in q:
+            for j in g[i]:
+                indeg[j] -= 1
+                if indeg[j] == 0:
+                    ans.append(j)
+                    q.append(j)
+        return ans