Fix goreport bug

Author: halfrost

leetcode/0116.Populating-Next-Right-Pointers-in-Each-Node/116.Populating Next Right Pointers in Each Node.go

@@ -7,7 +7,7 @@ type Node struct {
 	Next  *Node
 }
 
-//解法一：迭代
+// 解法一：迭代
 func connect(root *Node) *Node {
 	if root == nil {
 		return root

leetcode/0116.Populating-Next-Right-Pointers-in-Each-Node/116.Populating Next Right Pointers in Each Node_test.go

@@ -22,7 +22,7 @@ type ans116 struct {
 	one *Node
 }
 
-func newQuestionNode()*Node{
+func newQuestionNode() *Node {
 	node7 := &Node{}
 	node7.Val = 7
 
@@ -55,7 +55,7 @@ func newQuestionNode()*Node{
 	return node1
 }
 
-func newResultNode()*Node{
+func newResultNode() *Node {
 	node7 := &Node{}
 	node7.Val = 7
 
@@ -114,4 +114,4 @@ func Test_Problem116(t *testing.T) {
 		fmt.Printf("【output】:%v      \n", connect(p.one))
 	}
 	fmt.Printf("\n\n\n")
-}
+}

leetcode/0306.Additive-Number/306. Additive Number.go

@@ -35,7 +35,7 @@ func max(a int, b int) int {
 	return b
 }
 
-//Propagate for rest of the string
+// Propagate for rest of the string
 func recursiveCheck(num string, x1 int, x2 int, left int) bool {
 	if left == len(num) {
 		return true

leetcode/0372.Super-Pow/372. Super Pow.go

@@ -8,10 +8,11 @@ package leetcode
 // 模运算性质五：ab % p = ((a % p) * ( b % p)) % p, 其中 ab 是一个数字，如:2874，98374 等等
 // 举个例子
 // 12345^678 % 1337 = (12345^670 * 12345^8) % 1337
-//				    = ((12345^670 % 1337) * (12345^8 % 1337)) % 1337  ---> 利用性质 三
+//
+//	                = ((12345^670 % 1337) * (12345^8 % 1337)) % 1337  ---> 利用性质 三
 //				    = (((12345^67)^10 % 1337) * (12345^8 % 1337)) % 1337  ---> 乘方性质
-//                  = ((12345^67 % 1337)^10) % 1337 * (12345^8 % 1337)) % 1337  ---> 利用性质 四
-//				    = (((12345^67 % 1337)^10) * (12345^8 % 1337)) % 1337  ---> 反向利用性质 三
+//		            = ((12345^67 % 1337)^10) % 1337 * (12345^8 % 1337)) % 1337  ---> 利用性质 四
+//					= (((12345^67 % 1337)^10) * (12345^8 % 1337)) % 1337  ---> 反向利用性质 三
 func superPow(a int, b []int) int {
 	res := 1
 	for i := 0; i < len(b); i++ {

leetcode/0401.Binary-Watch/401. Binary Watch.go

@@ -76,11 +76,11 @@ func readBinaryWatch1(num int) []string {
 	return res
 }
 
-/// ---------------------------------------
-/// ---------------------------------------
-/// ---------------------------------------
-/// ---------------------------------------
-/// ---------------------------------------
+// / ---------------------------------------
+// / ---------------------------------------
+// / ---------------------------------------
+// / ---------------------------------------
+// / ---------------------------------------
 // 以下是打表用到的函数
 // 调用 findReadBinaryWatchMinute(num, 0, c, &res) 打表
 func findReadBinaryWatchMinute(target, index int, c []int, res *[]string) {

leetcode/0509.Fibonacci-Number/509. Fibonacci Number.go

@@ -111,19 +111,19 @@ func fib5(N int) int {
 
 // 解法七 协程版，但是时间特别慢，不推荐，放在这里只是告诉大家，写 LeetCode 算法题的时候，启动 goroutine 特别慢
 func fib6(N int) int {
-    return <-fibb(N)
+	return <-fibb(N)
 }
 
-func fibb(n int) <- chan int {
-    result := make(chan int)
-    go func() {
-        defer close(result)
-        
-        if n <= 1 {
-            result <- n
-            return
-        }
-        result <- <-fibb(n-1) + <-fibb(n-2)
-    }()
-    return result
-}
+func fibb(n int) <-chan int {
+	result := make(chan int)
+	go func() {
+		defer close(result)
+
+		if n <= 1 {
+			result <- n
+			return
+		}
+		result <- <-fibb(n-1) + <-fibb(n-2)
+	}()
+	return result
+}

leetcode/0589.N-ary-Tree-Preorder-Traversal/589. N-ary Tree Preorder Traversal.go

@@ -1,6 +1,6 @@
 package leetcode
 
-//  Definition for a Node.
+// Definition for a Node.
 type Node struct {
 	Val      int
 	Children []*Node

leetcode/0648.Replace-Words/648. Replace Words.go

@@ -34,7 +34,7 @@ func findWord(roots map[byte][]string, word []byte) bool {
 	return false
 }
 
-//解法二 Trie
+// 解法二 Trie
 func replaceWords1(dict []string, sentence string) string {
 	trie := Constructor208()
 	for _, v := range dict {