Add dict support for the default resolver (#174)

Author: caseywebdev

graphql/execution/tests/test_resolve.py

@@ -224,3 +224,10 @@ def resolver(source, info, **args):
     assert result.data == {
         "test": '["Source!",{"a_input":{"input_recursive":{"input_one":"SourceRecursive!"}}}]'
     }
+
+
+def test_default_resolve_works_with_dicts():
+    schema = _test_schema(GraphQLField(GraphQLString))
+    result = graphql(schema, "{ test }", {"test": "testValue"})
+    assert not result.errors
+    assert result.data == {"test": "testValue"}

graphql/execution/utils.py

@@ -349,11 +349,14 @@ def get_field_entry_key(node):
 
 
 def default_resolve_fn(source, info, **args):
-    # type: (Any, ResolveInfo, **Any) -> Union[int, str]
+    # type: (Any, ResolveInfo, **Any) -> Optional[Any]
     """If a resolve function is not given, then a default resolve behavior is used which takes the property of the source object
     of the same name as the field and returns it as the result, or if it's a function, returns the result of calling that function."""
     name = info.field_name
-    property = getattr(source, name, None)
+    if isinstance(source, dict):
+        property = source.get(name)
+    else:
+        property = getattr(source, name, None)
     if callable(property):
         return property()
     return property