Allow outputting literal expressions as source blocks

Author: russcam

src/CodeGeneration/DocGenerator/StringExtensions.cs

@@ -218,7 +218,7 @@ public static string RemoveNumberOfLeadingTabsOrSpacesAfterNewline(this string i
 
 		public static string[] SplitOnNewLines(this string input, StringSplitOptions options) => input.Split(new[] { "\r\n", "\n" }, options);
 
-		public static bool TryGetJsonForAnonymousType(this string anonymousTypeString, out string json)
+		public static bool TryGetJsonForExpressionSyntax(this string anonymousTypeString, out string json)
 		{
 			json = null;
 

src/CodeGeneration/DocGenerator/SyntaxNodeExtensions.cs

@@ -71,12 +71,11 @@ public static bool TryGetJsonForSyntaxNode(this SyntaxNode node, out string json
 		{
 			json = null;
 
-			// find the first anonymous object or new object expression
-			var creationExpressionSyntax = node.DescendantNodes()
-				.FirstOrDefault(n => n is AnonymousObjectCreationExpressionSyntax || n is ObjectCreationExpressionSyntax);
+			// find the first anonymous object, new object expression, or literal expression
+			var syntax = node.DescendantNodes()
+				.FirstOrDefault(n => n is AnonymousObjectCreationExpressionSyntax || n is ObjectCreationExpressionSyntax || n is LiteralExpressionSyntax);
 
-			return creationExpressionSyntax != null &&
-				creationExpressionSyntax.ToFullString().TryGetJsonForAnonymousType(out json);
+			return syntax != null && syntax.ToFullString().TryGetJsonForExpressionSyntax(out json);
 		}
 
 		/// <summary>