feat: add python solution to leetcode problem: No.1295

添加leetcode题解：1295. 统计位数为偶数的数字

Author: yanglbme

solution/1200-1299/1295.Find Numbers with Even Number of Digits/README.md

@@ -42,15 +42,20 @@
 
 ## 解法
 <!-- 这里可写通用的实现逻辑 -->
-首先将数组元素转换为字符串,判断字符串长度是否为偶数即可
+首先将数组元素转换为字符串,判断字符串长度是否为偶数即可。
 
 <!-- tabs:start -->
 
 ### **Python3**
 <!-- 这里可写当前语言的特殊实现逻辑 -->
 
 ```python
-
+class Solution:
+    def findNumbers(self, nums: List[int]) -> int:
+        res = 0
+        for num in nums:
+            res += (len(str(num)) & 1) == 0
+        return res
 ```
 
 ### **Java**
@@ -60,10 +65,8 @@
 class Solution {
     public int findNumbers(int[] nums) {
         int res = 0;
-        for (int i = 0; i < nums.length; i++) {
-            if (((String.valueOf(nums[i]).length()) & 1) == 0) {
-                res++;
-            }
+        for (int num : nums) {
+            res += (String.valueOf(num).length() & 1) == 0 ? 1 : 0;
         }
         return res;
     }

solution/1200-1299/1295.Find Numbers with Even Number of Digits/README_EN.md

@@ -46,13 +46,26 @@ Only 1771 contains an even number of digits.
 ### **Python3**
 
 ```python
-
+class Solution:
+    def findNumbers(self, nums: List[int]) -> int:
+        res = 0
+        for num in nums:
+            res += (len(str(num)) & 1) == 0
+        return res
 ```
 
 ### **Java**
 
 ```java
-
+class Solution {
+    public int findNumbers(int[] nums) {
+        int res = 0;
+        for (int num : nums) {
+            res += (String.valueOf(num).length() & 1) == 0 ? 1 : 0;
+        }
+        return res;
+    }
+}
 ```
 
 ### **...**

solution/1200-1299/1295.Find Numbers with Even Number of Digits/Solution.java

@@ -1,11 +1,9 @@
 class Solution {
     public int findNumbers(int[] nums) {
         int res = 0;
-        for (int i = 0; i < nums.length; i++) {
-            if (((String.valueOf(nums[i]).length()) & 1) == 0) {
-                res++;
-            }
+        for (int num : nums) {
+            res += (String.valueOf(num).length() & 1) == 0 ? 1 : 0;
         }
         return res;
     }
-}
+}

solution/1200-1299/1295.Find Numbers with Even Number of Digits/Solution.py

@@ -0,0 +1,6 @@
+class Solution:
+    def findNumbers(self, nums: List[int]) -> int:
+        res = 0
+        for num in nums:
+            res += (len(str(num)) & 1) == 0
+        return res