feat: add solutions to leetcode problem: No.0551

551. Student Attendance Record I

Author: yanglbme

README.md

@@ -123,7 +123,7 @@
 - [只出现一次的数字 II](/solution/0100-0199/0137.Single%20Number%20II/README.md)
 - [只出现一次的数字 III](/solution/0200-0299/0260.Single%20Number%20III/README.md)
 - [错误的集合](/solution/0600-0699/0645.Set%20Mismatch/README.md)
-- [二进制中 1 的个数](/lcof/面试题15.%20二进制中1的个数/README.md)
+- [位 1 的个数](/solution/0100-0199/0191.Number%20of%201%20Bits/README.md)
 - [计数质数](/solution/0200-0299/0204.Count%20Primes/README.md)
 - [不用加减乘除做加法](/lcof/面试题65.%20不用加减乘除做加法/README.md)
 - [丢失的数字](/solution/0200-0299/0268.Missing%20Number/README.md)

README_EN.md

@@ -119,6 +119,7 @@ Complete solutions to [LeetCode](https://leetcode-cn.com/problemset/all/), [LCOF
 - [Single Number II](/solution/0100-0199/0137.Single%20Number%20II/README_EN.md)
 - [Single Number III](/solution/0200-0299/0260.Single%20Number%20III/README_EN.md)
 - [Set Mismatch](/solution/0600-0699/0645.Set%20Mismatch/README_EN.md)
+- [Number of 1 Bits](/solution/0100-0199/0191.Number%20of%201%20Bits/README_EN.md)
 - [Count Primes](/solution/0200-0299/0204.Count%20Primes/README_EN.md)
 - [Missing Number](/solution/0200-0299/0268.Missing%20Number/README_EN.md)
 

solution/0500-0599/0551.Student Attendance Record I/README.md

@@ -40,15 +40,22 @@
 <!-- 这里可写当前语言的特殊实现逻辑 -->
 
 ```python
-
+class Solution:
+    def checkRecord(self, s: str) -> bool:
+        return s.count('A') <= 1 and 'LLL' not in s
 ```
 
 ### **Java**
 
 <!-- 这里可写当前语言的特殊实现逻辑 -->
 
 ```java
-
+class Solution {
+    public boolean checkRecord(String s) {
+        int i = s.indexOf("A");
+        return (i == -1 || s.lastIndexOf("A") == i) && !s.contains("LLL");
+    }
+}
 ```
 
 ### **...**

solution/0500-0599/0551.Student Attendance Record I/README_EN.md

@@ -57,13 +57,20 @@ A student could be rewarded if his attendance record doesn't contain <b>more tha
 ### **Python3**
 
 ```python
-
+class Solution:
+    def checkRecord(self, s: str) -> bool:
+        return s.count('A') <= 1 and 'LLL' not in s
 ```
 
 ### **Java**
 
 ```java
-
+class Solution {
+    public boolean checkRecord(String s) {
+        int i = s.indexOf("A");
+        return (i == -1 || s.lastIndexOf("A") == i) && !s.contains("LLL");
+    }
+}
 ```
 
 ### **...**

solution/0500-0599/0551.Student Attendance Record I/Solution.java

@@ -0,0 +1,6 @@
+class Solution {
+    public boolean checkRecord(String s) {
+        int i = s.indexOf("A");
+        return (i == -1 || s.lastIndexOf("A") == i) && !s.contains("LLL");
+    }
+}

solution/0500-0599/0551.Student Attendance Record I/Solution.py

@@ -0,0 +1,3 @@
+class Solution:
+    def checkRecord(self, s: str) -> bool:
+        return s.count('A') <= 1 and 'LLL' not in s