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‎README.md‎

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# 力扣题库（完整版）
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3-
> 最后更新日期： **2023.10.25**
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> 最后更新日期： **2023.11.03**
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>
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> 使用脚本前请务必仔细完整阅读本 `README.md` 文件
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‎leetcode-cn/origin-data.json‎

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‎leetcode-cn/originData/[no content]market-analysis-iii.json‎

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{
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"data": {
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"question": {
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"questionId": "3205",
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"questionFrontendId": "2922",
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"categoryTitle": "Database",
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"boundTopicId": 2509032,
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"title": "Market Analysis III",
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"titleSlug": "market-analysis-iii",
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"content": null,
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"translatedTitle": null,
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"isPaidOnly": true,
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"difficulty": "Medium",
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"likes": 0,
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"similarQuestions": "[]",
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"stats": "{\"totalAccepted\": \"14\", \"totalSubmission\": \"23\", \"totalAcceptedRaw\": 14, \"totalSubmissionRaw\": 23, \"acRate\": \"60.9%\"}",
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"hints": [],
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"solution": null,
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"status": null,
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"sampleTestCase": "{\"headers\": {\"Users\": [\"seller_id\", \"join_date\", \"favorite_brand\"],\"Orders\":[\"order_id\",\"order_date\",\"item_id\",\"seller_id\"],\"Items\":[\"item_id\",\"item_brand\"]},\"rows\":{\"Users\":[[1,\"2019-01-01\",\"Lenovo\"],[2,\"2019-02-09\",\"Samsung\"],[3,\"2019-01-19\",\"LG\"]],\"Orders\":[[1,\"2019-08-01\",4,2],[2,\"2019-08-02\",2,3],[3,\"2019-08-03\",3,3],[4,\"2019-08-04\",1,2],[5,\"2019-08-04\",4,2]],\"Items\":[[1,\"Samsung\"],[2,\"Lenovo\"],[3,\"LG\"],[4,\"HP\"]]}}",
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"metaData": "{\"mysql\":[\"Create table If Not Exists Users (seller_id int, join_date date, favorite_brand varchar(10))\",\"Create table If Not Exists Orders (order_id int, order_date date, item_id int, seller_id int)\",\"Create table If Not Exists Items (item_id int, item_brand varchar(10))\"],\"mssql\":[\"Create table Users (seller_id int, join_date date, favorite_brand varchar(10))\",\"Create table Orders (order_id int, order_date date, item_id int, seller_id int)\",\"Create table Items (item_id int, item_brand varchar(10))\"],\"oraclesql\":[\"Create table Users (seller_id int, join_date date, favorite_brand varchar(10))\",\"Create table Orders (order_id int, order_date date, item_id int, seller_id int)\",\"Create table Items (item_id int, item_brand varchar(10))\",\"ALTER SESSION SET nls_date_format='YYYY-MM-DD'\"],\"database\":true,\"languages\":[\"mysql\",\"mssql\",\"oraclesql\"],\"database_schema\":{\"Users\":{\"seller_id\":\"INT\",\"join_date\":\"DATE\",\"favorite_brand\":\"VARCHAR(10)\"},\"Orders\":{\"order_id\":\"INT\",\"order_date\":\"DATE\",\"item_id\":\"INT\",\"seller_id\":\"INT\"},\"Items\":{\"item_id\":\"INT\",\"item_brand\":\"VARCHAR(10)\"}}}",
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"judgerAvailable": true,
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"judgeType": "large",
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"mysqlSchemas": [
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"Create table If Not Exists Users (seller_id int, join_date date, favorite_brand varchar(10))",
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"Create table If Not Exists Orders (order_id int, order_date date, item_id int, seller_id int)",
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"Create table If Not Exists Items (item_id int, item_brand varchar(10))",
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"Truncate table Users",
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"insert into Users (seller_id, join_date, favorite_brand) values ('1', '2019-01-01', 'Lenovo')",
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"insert into Users (seller_id, join_date, favorite_brand) values ('2', '2019-02-09', 'Samsung')",
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"insert into Users (seller_id, join_date, favorite_brand) values ('3', '2019-01-19', 'LG')",
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"Truncate table Orders",
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"insert into Orders (order_id, order_date, item_id, seller_id) values ('1', '2019-08-01', '4', '2')",
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"insert into Orders (order_id, order_date, item_id, seller_id) values ('2', '2019-08-02', '2', '3')",
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"insert into Orders (order_id, order_date, item_id, seller_id) values ('3', '2019-08-03', '3', '3')",
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"insert into Orders (order_id, order_date, item_id, seller_id) values ('4', '2019-08-04', '1', '2')",
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"insert into Orders (order_id, order_date, item_id, seller_id) values ('5', '2019-08-04', '4', '2')",
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"Truncate table Items",
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"insert into Items (item_id, item_brand) values ('1', 'Samsung')",
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"insert into Items (item_id, item_brand) values ('2', 'Lenovo')",
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"insert into Items (item_id, item_brand) values ('3', 'LG')",
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"insert into Items (item_id, item_brand) values ('4', 'HP')"
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],
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"style": "LEETCODE",
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"exampleTestcases": "{\"headers\": {\"Users\": [\"seller_id\", \"join_date\", \"favorite_brand\"],\"Orders\":[\"order_id\",\"order_date\",\"item_id\",\"seller_id\"],\"Items\":[\"item_id\",\"item_brand\"]},\"rows\":{\"Users\":[[1,\"2019-01-01\",\"Lenovo\"],[2,\"2019-02-09\",\"Samsung\"],[3,\"2019-01-19\",\"LG\"]],\"Orders\":[[1,\"2019-08-01\",4,2],[2,\"2019-08-02\",2,3],[3,\"2019-08-03\",3,3],[4,\"2019-08-04\",1,2],[5,\"2019-08-04\",4,2]],\"Items\":[[1,\"Samsung\"],[2,\"Lenovo\"],[3,\"LG\"],[4,\"HP\"]]}}",
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"__typename": "QuestionNode"
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}
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}

‎leetcode-cn/originData/[no content]maximum-profitable-triplets-with-increasing-prices-ii.json‎

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"categoryTitle": "Algorithms",
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"boundTopicId": 2508831,
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"title": "Maximum Profitable Triplets With Increasing Prices II",
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"titleSlug": "maximum-profitable-triplets-with-increasing-prices-ii",
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"stats": "{\"totalAccepted\": \"31\", \"totalSubmission\": \"33\", \"totalAcceptedRaw\": 31, \"totalSubmissionRaw\": 33, \"acRate\": \"93.9%\"}",
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"hints": [
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"Let's fix the middle chosen item for instance index <code>j</code>.",
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"Let’s define an array <code>max_right</code>, where <code>max_right[j]</code> represents the maximum <code>profit[k]</code> for every index <code>k > j</code> such that <code>prices[k] > prices[j]</code>.",
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"Consider using a Fenwick tree to fill the <code>max_right</code>.",
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"Do the same for items with an index <code>i < j</code> such that <code>prices[i] < prices[j]</code> and find the maximum <code>profit[i]</code> among them. Let's call this array <code>max_left</code>.",
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"Now the profit when an item with the index <code>j</code> is the middle one would be <code>profit[j] + max_right[j] + max_left[j]</code>.",
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"Finally, do the above procedure for all <code>j</code>'s and find the maximum profit among them. That would be the final answer."
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],
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"solution": null,
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"status": null,
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"metaData": "{\n \"name\": \"maxProfit\",\n \"params\": [\n {\n \"name\": \"prices\",\n \"type\": \"integer[]\"\n },\n {\n \"type\": \"integer[]\",\n \"name\": \"profits\"\n }\n ],\n \"return\": {\n \"type\": \"integer\"\n }\n}",
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