Added participation grade solution

Author: Citrus716

2_intermediate/chapter9/solutions/participation_grade.py

@@ -0,0 +1,37 @@
+# Warning: can be challenging
+#
+# A teacher is given a list of students. The number of occurences of a student's
+# name in the list is the number of times the student participated in this week.
+# If a student has more the 7 participation, then got an A. If a student has
+# more than 3 but less than 8, the student got a B. If a student has more than
+# 0 but less than 4, the student got a C. 
+#
+# Make a dictionary with the keys as the students' name and the values as the
+# corresponding student's letter grade. Print the dictionary
+#
+# Write your code below
+
+
+participation_occurences = ["Sam", "Dan", "Bob", "Dan", "Sam", "Sam",
+                            "Bob", "Dan", "Dan", "Ivan", "Ivan",
+                            "Ray", "Sam", "Sam", "Dan", "Ivan", "Ivan",
+                            "Ray", "Dan", "Ivan", "Ivan", "Sam", "Dan",
+                            "Ray", "Sam", "Dan", "Bob", "Dan", "Sam", 
+                            "Sam", "Dan", "Bob", "Dan", "Sam", "Sam"]
+
+grade_dict = {}
+for student in participation_occurences:
+    if student not in grade_dict:
+        grade_dict[student] = 1
+    else:
+        grade_dict[student] += 1
+
+for student in grade_dict:
+    if grade_dict[student] > 7:
+        grade_dict[student] = "A"
+    elif grade_dict[student] >3:
+        grade_dict[student] = "B"
+    else:
+        grade_dict[student] = "C"
+
+print(grade_dict)