feat: updates lexicographically condition

Author: PabLim-Par

lesson_07/conditionals/src/lesson7.ts

@@ -25,9 +25,9 @@ export function compareStrings(a: string, b: string): number {
   // The distance will be a number less than 0 if string `a` is lexicographically less than `b`, 1
   // if it is greater, and 0 if the strings are equal.
   const distance = computeLexicographicDistance(a, b);
-  if (a < b) {
+  if (distance < 0) {
     return -1;
-  } else if (a > b) {
+  } else if (distance > 0) {
     return 1;
   } else {
     return 0;