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Author: Saptarshi-prog

Integer to English Word.py

@@ -0,0 +1,50 @@
+# -*- coding: utf-8 -*-
+"""
+Created on Fri Sep 11 20:04:48 2020
+
+@author: Saptarshi
+"""
+
+num = int(input())
+
+TENS = {30: 'Thirty', 40: 'Forty', 50: 'Fifty', 60: 'Sixty', 70: 'Seventy', 80: 'Eighty', 90: 'Ninety'}
+
+ZERO_TO_TWENTY = (
+    'Zero', 'One', 'Two', 'Three', 'Four', 'Five', 'Six', 'Seven', 'Eight', 'Nine', 'Ten',
+    'Eleven', 'Twelve', 'Thirteen', 'Fourteen', 'Fifteen', 'Sixteen', 'Seventeen', 'Eighteen',
+    'Nineteen', 'Twenty'
+)
+
+def number_to_english(n):
+    if any(not x.isdigit() for x in str(n)):
+        return ''
+
+    if n <= 20:
+        return ZERO_TO_TWENTY[n]
+    elif n < 100 and n % 10 == 0:
+        return TENS[n]
+    elif n < 100:
+        return number_to_english(n - (n % 10)) + ' ' + number_to_english(n % 10)
+    elif n < 1000 and n % 100 == 0:
+        return number_to_english(int(n/100)) + ' Hundred'
+    elif n < 1000:
+        return number_to_english(int(n/100)) + ' Hundred ' + number_to_english(n % 100)
+    elif n<1000000 and n>=1000 and n%1000==0:
+        return number_to_english(int(n/1000)) + ' Thousand'
+    elif n < 1000000:
+        return number_to_english(int(n/1000)) + ' Thousand ' + number_to_english(n % 1000)
+    elif n<1000000000 and n>=1000000 and n%1000000==0:
+        return number_to_english(int(n/1000000)) + ' Million'
+    elif n<1000000000 and n>=1000000:
+        return number_to_english(int(n/1000000)) + ' Million ' + number_to_english(n%1000000)
+    elif n<2**31-1 and n>=1000000000 and n%1000000000==0:
+        return number_to_english(int(n/1000000000)) + ' Billion'
+    elif n<=2**31-1 and n>=1000000000:
+        return number_to_english(int(n/1000000000)) + ' Billion ' + number_to_english(n%1000000000)
+    
+    return ''
+
+
+
+print(number_to_english(num))
+