fixed a but in equality operator

Author: RednibCoding

docs/examples.html

@@ -38,10 +38,10 @@ <h2>Code Examples</h2>
 
 # Fibonacci
 fibonacci = fun(n) {
-    if n <= 1 then n
+    if n <= 1 then return = n
     fibonacci(n - 1) + fibonacci(n - 2)
 }
-print(fibonacci(10)) # Outputs 55
+print(fibonacci(10)) # output 55
             </code>
             </pre>
         </section>

evaluator.go

@@ -124,9 +124,10 @@ func (e *Evaluator) evaluate(exp *Expr, env *Environment) interface{} {
 		return env.Set(exp.Left.Value.(string), e.evaluate(exp.Right, env), exp)
 
 	case Binary:
-		return applyBinaryOp(exp.Operator,
-			e.evaluate(exp.Left, env),
-			e.evaluate(exp.Right, env), exp)
+		a := e.evaluate(exp.Left, env)
+		b := e.evaluate(exp.Right, env)
+		result := applyBinaryOp(exp.Operator, a, b, exp)
+		return result
 
 	case Unary:
 		return applyUnaryOp(exp.Operator,
@@ -378,9 +379,9 @@ func applyBinaryOp(op string, a, b interface{}, exp *Expr) interface{} {
 	case ">=":
 		return num(a) >= num(b)
 	case "==":
-		return a == b
+		return num(a) == num(b)
 	case "!=":
-		return a != b
+		return num(a) != num(b)
 	default:
 		Error(exp, "Can't apply operator %s", op)
 		return nil

example/test.rune

@@ -1,3 +1,16 @@
+factorial = fun(n) {
+    if n == 0 then return = 1
+    return = n * factorial(n - 1)
+}
+println(factorial(5)) # Outputs 120
+
+exit()
+
+fibonacci = fun(n) {
+    if n <= 1 then return = n
+    fibonacci(n - 1) + fibonacci(n - 2)
+}
+print(fibonacci(10)) # output 55
 
 a = 10