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X v_i & = \sigma_i u_i , \quad i = 1, \ldots, p \cr
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X v_i & = 0 , \quad i = p+1, \ldots, n
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\end{aligned}
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$$ (eq:orthoortho1)
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Equations {eq}`eq:orthoortho1` tell how the transformation $X$ maps a pair of orthonormal vectors $v_i, v_j$ for $i$ and $j$ both less than or equal to the rank $p$ of $X$ into a pair of orthonormal vectors $u_i, u_j$.
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Equations {eq}`eq:Xfour1a` assert that
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$$
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\begin{aligned}
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{\mathcal C}(X) & = {\mathcal C}(U_L) \cr
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{\mathcal N}(X) & = {\mathcal C} (V_R)
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\end{aligned}
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$$
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Taking transposes on both sides of representation {eq}`eq:fullSVDpartition` implies
Notice how equations {eq}`eq:orthoortho2` assert that the transformation $X^T$ maps a pairsof distinct orthonormal vectors $u_i, u_j$ for $i$ and $j$ both less than or equal to the rank $p$ of $X$ into a pair of distinct orthonormal vectors $v_i, v_j$ .
These matrices are related to the four fundamental subspaces of $X$ in the following ways:
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Thus, taken together, the systems of quations {eq}`eq:Xfour1a` and {eq}`eq:Xfour1b`
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describe the four fundamental subspaces of $X$ in the following ways:
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$$
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\begin{aligned}
@@ -182,7 +266,6 @@ $$
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$$ (eq:fourspaceSVD)
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Here ${\mathcal C}$ denotes a column space, ${\mathcal N}$ denotes a null space, and ${\mathcal R}$ denotes a row space.
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Since $U$ and $V$ are both orthonormal matrices, collection {eq}`eq:fourspaceSVD` asserts that
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@@ -192,9 +275,9 @@ Since $U$ and $V$ are both orthonormal matrices, collection {eq}`eq:fourspaceSVD
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* $V_R$ is an orthonormal basis for the null space of $X$
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The four claims in {eq}`eq:fourspaceSVD` can be verified by performing the multiplications called for by the right side of {eq}`eq:fullSVDpartition` and interpreting them.
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We have verified the four claims in {eq}`eq:fourspaceSVD` simply by performing the multiplications called for by the right side of {eq}`eq:fullSVDpartition` and reading them.
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Although we won't go through the details of that verification here, we will note that the claims in {eq}`eq:fourspaceSVD` and the fact that $U$ and $V$ are both unitary (i.e, orthonormal) matrices immediately implies
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The claims in {eq}`eq:fourspaceSVD` and the fact that $U$ and $V$ are both unitary (i.e, orthonormal) matrices imply
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that
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* the column space of $X$ is orthogonal to the null space of of $X^T$
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