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lectures/sd_foundations.md

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<!-- #region -->
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## Elements of Supply and Demand
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This lecture is about some linear models of equilibrium prices and quantities, one of the main topics
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* we'll derive **demand curves** from a consumer problem that maximizes a **utility function** subject to a **budget constraint**.
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* we'll derive **supply curves** from the problem of a producer who is price taker and maximizes his profits minus total costs that are described by a **cost function**.
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# Multiple goods
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Let
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* $\Pi$ be an $n\times n$ matrix,
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* $\Pi$ be an $m \times n$ matrix,
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* $c$ be an $n \times 1$ vector of consumptions of various goods,
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* $b$ be an $n \times 1$ vector of bliss points,
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* $b$ be an $m \times 1$ vector of bliss points,
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* $e$ be an $n \times 1$ vector of endowments, and
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* $p$ be an $n\times 1$ vector of prices
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* $p$ be an $n \times 1$ vector of prices
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We assume that $\Pi$ has an inverse $\Pi^{-1}$ and that $\Pi^\top \Pi$ is a positive definite matrix.
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* it follows that $\Pi^\top \Pi$ has an inverse.
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We assume that $\Pi$ has linearly independent columns, which implies that $\Pi^\top \Pi$ is a positive definite matrix.
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* it follows that $\Pi^\top \Pi$ has an inverse.
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The matrix $\Pi$ describes a consumer's willingness to substitute one good for every other good.
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We shall see below that $(\Pi^T \Pi)^{-1}$ is a matrix of slopes of (compensated) demand curves for $c$ with respect to a vector of prices:
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$$
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\frac{\partial c } {\partial p} = (\Pi^T \Pi)^{-1}
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\frac{\partial c } {\partial p} = (\Pi^T \Pi)^{-1}
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$$
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A consumer faces $p$ as a price taker and chooses $c$ to maximize the utility function
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$$
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-.5 (\Pi c -b) ^\top (\Pi c -b )
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-.5 (\Pi c -b) ^\top (\Pi c -b )
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$$ (eq:old0)
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subject to the budget constraint
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$$
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p ^\top (c -e ) = 0
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p^\top (c -e ) = 0
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$$ (eq:old2)
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We shall specify examples in which $\Pi$ and $b$ are such that it typically happens that
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$$
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\Pi c < < b
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\Pi c < < b
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$$ (eq:bversusc)
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so that utility function {eq}`eq:old2` tells us that the consumer has much less of each good than he wants.
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First-order conditions for $c$ are
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$$
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\frac{\partial L} {\partial c} = - \Pi^\top \Pi c + \Pi^\top b - \mu p = 0
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\frac{\partial L} {\partial c}
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= - \Pi^\top \Pi c + \Pi^\top b - \mu p = 0
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$$
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so that, given $\mu$, the consumer chooses
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$$
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c = \Pi^{-1} b - \Pi^{-1} (\Pi^\top)^{-1} \mu p
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c = (\Pi^\top \Pi )^{-1}(\Pi^\top b - \mu p )
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$$ (eq:old3)
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Substituting {eq}`eq:old3` into budget constraint {eq}`eq:old2` and solving for $\mu$ gives
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$$
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\mu(p,e) = \frac{p^\top (\Pi^{-1} b - e)}{p^\top (\Pi^\top \Pi )^{-1} p}.
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\mu(p,e) = \frac{p^\top ( \Pi^\top \Pi )^{-1} \Pi^\top b - p^\top e}{p^\top (\Pi^\top \Pi )^{-1} p}.
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$$ (eq:old4)
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Equation {eq}`eq:old4` tells how marginal utility of wealth depends on the endowment vector $e$ and the price vector $p$.
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**Remark:** Equation {eq}`eq:old4` is a consequence of imposing that $p^\top (c - e) = 0$. We could instead take $\mu$ as a parameter and use {eq}`eq:old3` and the budget constraint {eq}`eq:old2p` to solve for $W.$ Which way we proceed determines whether we are constructing a **Marshallian** or **Hicksian** demand curve.
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## Endowment economy, I
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We now study a pure-exchange economy, or what is sometimes called an endowment economy.
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**Exercise:** Verify that setting $\mu=2$ in {eq}`eq:old3` also implies that formula {eq}`eq:old4` is satisfied.
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## Digression: Marshallian and Hicksian Demand Curves
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**Remark:** Sometimes we'll use budget constraint {eq}`eq:old2` in situations in which a consumers's endowment vector $e$ is his **only** source of income. Other times we'll instead assume that the consumer has another source of income (positive or negative) and write his budget constraint as
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We'll discuss these distinct demand curves more below.
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## Endowment Economy, II
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Let's study a **pure exchange** economy without production.
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Assume the demand curves
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$$
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c_i = \Pi^{-1}b_i - (\Pi^\top \Pi)^{-1} \mu_i p
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c_i = (\Pi^\top \Pi )^{-1}(\Pi^\top b_i - \mu_i p )
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$$
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Competitive equilibrium then requires that
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$$
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e_1 + e_2 = \Pi^{-1} (b_1 + b_2) - (\Pi^\top \Pi)^{-1} (\mu_1 + \mu_2) p
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e_1 + e_2 =
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(\Pi^\top \Pi)^{-1}(\Pi^\top (b_1 + b_2) - (\mu_1 + \mu_2) p )
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$$
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which after a line or two of linear algebra implies that
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e = e_1 + e_2 .
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$$
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## Dynamics and Risk as Special Cases of Pure Exchange Economy
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Special cases of our $n$-good pure exchange model can be created to represent
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b = \begin{bmatrix} b_1 \cr b_2 \end{bmatrix}
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$$
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<!-- #endregion -->
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<!-- #region -->
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$$
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b = \begin{bmatrix} \sqrt{\lambda}b_1 \cr \sqrt{1-\lambda}b_2 \end{bmatrix}

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