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If $\bar{x}$ is an eigenvector corresponding to the eigenvalue $r(A)$ then all the vectors in the set
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$D := \{ x \in \mathbb{R}^2 : x = \alpha \bar{x} \; \text{for some} \; \alpha >0 \}$ are also eigenvectors corresponding
@@ -352,7 +371,7 @@ This is visualised below.
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```{code-cell} ipython3
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lm = LakeModel(α=0.01, λ=0.1, d=0.025, b=0.02)
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plot_time_paths(lm, x0=x0)
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````
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```
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Thus, while the sequence of iterates still move towards the dominant eigenvector $\bar{x}$ however in this case
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they converge to the origin.
@@ -471,7 +490,7 @@ Assume that $\alpha$ increases to $0.04$.
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The below graph illustrates that the line $D$ shifts downward, which indicates that the fraction of unemployment rises as the separation rate increases.
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````{code-cell} ipython3
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```{code-cell} ipython3
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fig, ax = plt.subplots(figsize=(10, 8))
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lm = LakeModel(α=0.01, λ=0.1, d=0.02, b=0.025)
@@ -485,7 +504,4 @@ ax.plot([0, s * lm.ū], [0, s * lm.ē], "r--", lw=1, label='set $D$, α=0.04')
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