improve coding style

Author: phullot

pycodestyle.py

@@ -444,27 +444,29 @@ def is_a_slice(line, space_pos):
         parentheses_brackets_braces = list()
         for i in range(space_pos):
             c = line[i]
-            if c in '[({':
+            if c in "[({":
                 # add it to the stack
                 parentheses_brackets_braces.append((c, i))
-            elif c in '])}':
+            elif c in "])}":
                 # unstack last item and check consistency
                 last_opened = parentheses_brackets_braces.pop()[0]
-                expected_close = {'{': '}', '(': ')', '[': ']'}[last_opened]
+                expected_close = {"{": "}", "(": ")", "[": "]"}[last_opened]
                 if c != expected_close:  # invalid Python code
                     return False
-        is_within_brackets = (len(parentheses_brackets_braces) > 0 and
-                              parentheses_brackets_braces[-1][0] == '[')
+        is_within_brackets = (
+            len(parentheses_brackets_braces) > 0
+            and parentheses_brackets_braces[-1][0] == "["
+        )
 
         is_lambda_expr = False
         if is_within_brackets:
             # check for a lambda expression nested in brackets
             if space_pos > 6:
                 last_opened = parentheses_brackets_braces[-1]
                 between_bracket_colon = line[last_opened[1] + 1: space_pos]
-                is_lambda_expr = 'lambda' in between_bracket_colon
+                is_lambda_expr = "lambda" in between_bracket_colon
 
-        return (is_within_brackets and not is_lambda_expr)
+        return is_within_brackets and not is_lambda_expr
 
     line = logical_line
     for match in EXTRANEOUS_WHITESPACE_REGEX.finditer(line):
@@ -474,12 +476,15 @@ def is_a_slice(line, space_pos):
         if text == char + ' ':
             # assert char in '([{'
             yield found + 1, "E201 whitespace after '%s'" % char
-        elif (line[found - 1] != ',' and
-              not (char == ':' and is_a_slice(line, found))):
-            code = ('E202' if char in '}])' else 'E203')  # if char in ',;:'
+        elif (
+            line[found - 1] != ','
+            and not (char == ':' and is_a_slice(line, found))
+        ):
+            code = "E202" if char in "}])" else "E203"  # if char in ',;:'
             yield found, "%s whitespace before '%s'" % (code, char)
 
 
+
 @register_check
 def whitespace_around_keywords(logical_line):
     r"""Avoid extraneous whitespace around keywords.