for signed overflowing remainder, delay comparing lhs with MIN

Since the wrapped remainder is going to be 0 for all cases when the rhs is -1,
there is no need to divide in this case. Comparing the lhs with MIN is only done
for the overflow bool. In particular, this results in better code generation for
wrapping remainder, which discards the overflow bool completely.

Author: tspiteri

library/core/src/num/int_macros.rs

@@ -1533,9 +1533,8 @@ macro_rules! int_impl {
         #[must_use = "this returns the result of the operation, \
                       without modifying the original"]
         pub const fn overflowing_rem(self, rhs: Self) -> (Self, bool) {
-            // Using `&` helps LLVM see that it is the same check made in division.
-            if unlikely!((self == Self::MIN) & (rhs == -1)) {
-                (0, true)
+            if unlikely!(rhs == -1) {
+                (0, self == Self::MIN)
             } else {
                 (self % rhs, false)
             }
@@ -1565,9 +1564,8 @@ macro_rules! int_impl {
                       without modifying the original"]
         #[inline]
         pub const fn overflowing_rem_euclid(self, rhs: Self) -> (Self, bool) {
-            // Using `&` helps LLVM see that it is the same check made in division.
-            if unlikely!((self == Self::MIN) & (rhs == -1)) {
-                (0, true)
+            if unlikely!(rhs == -1) {
+                (0, self == Self::MIN)
             } else {
                 (self.rem_euclid(rhs), false)
             }