task: #3611

Author: Ivanbyone

README.md

@@ -192,6 +192,7 @@ Useful for preparing for technical interviews and improving your SQL skills.
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     - [3601. Find Drivers with Improved Fuel Efficiency](./leetcode/medium/3601.%20Find%20Drivers%20with%20Improved%20Fuel%20Efficiency.sql)
+    - [3611. Find Overbooked Employees](./leetcode/medium/3611.%20Find%20Overbooked%20Employees.sql)
 3. [Hard](./leetcode/hard/)
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leetcode/medium/3611. Find Overbooked Employees.sql

@@ -0,0 +1,60 @@
+/*
+Question 3611. Find Overbooked Employees
+Link: https://leetcode.com/problems/find-overbooked-employees/description/?envType=problem-list-v2&envId=database
+
+Table: employees
+
++---------------+---------+
+| Column Name   | Type    |
++---------------+---------+
+| employee_id   | int     |
+| employee_name | varchar |
+| department    | varchar |
++---------------+---------+
+employee_id is the unique identifier for this table.
+Each row contains information about an employee and their department.
+Table: meetings
+
++---------------+---------+
+| Column Name   | Type    |
++---------------+---------+
+| meeting_id    | int     |
+| employee_id   | int     |
+| meeting_date  | date    |
+| meeting_type  | varchar |
+| duration_hours| decimal |
++---------------+---------+
+meeting_id is the unique identifier for this table.
+Each row represents a meeting attended by an employee. meeting_type can be 'Team', 'Client', or 'Training'.
+Write a solution to find employees who are meeting-heavy - employees who spend more than 50% of their working time in meetings during any given week.
+
+Assume a standard work week is 40 hours
+Calculate total meeting hours per employee per week (Monday to Sunday)
+An employee is meeting-heavy if their weekly meeting hours > 20 hours (50% of 40 hours)
+Count how many weeks each employee was meeting-heavy
+Only include employees who were meeting-heavy for at least 2 weeks
+Return the result table ordered by the number of meeting-heavy weeks in descending order, then by employee name in ascending order.
+*/
+
+WITH weeks_stats AS (
+    SELECT
+        employee_id,
+        EXTRACT(WEEK FROM meeting_date) AS week, --noqa: RF04
+        SUM(duration_hours) AS meet
+    FROM meetings
+    GROUP BY employee_id, week
+    HAVING SUM(duration_hours) > 20
+)
+
+SELECT 
+    e.employee_id,
+    e.employee_name,
+    e.department,
+    COUNT(e.employee_id) AS meeting_heavy_weeks
+FROM weeks_stats AS ws
+LEFT JOIN 
+    employees AS e
+    ON ws.employee_id = e.employee_id
+GROUP BY e.employee_id, e.employee_name, e.department
+HAVING COUNT(e.employee_id) >= 2
+ORDER BY meeting_heavy_weeks DESC, e.employee_name ASC