task: #601

Author: Ivanbyone

README.md

@@ -180,6 +180,7 @@ Useful for preparing for technical interviews and improving your SQL skills.
     - [3497. Analyze Subscription Conversion](./leetcode/medium/3497.%20Analyze%20Subscription%20Conversion.sql)
 3. [Hard](./leetcode/hard/)
     - [185. Department Top Three Salaries](./leetcode/hard/185.%20Department%20Top%20Three%20Salaries.sql)
+    - [601. Human Traffic of Stadium](./leetcode/hard/601.%20Human%20Traffic%20of%20Stadium.sql)
     - [3374. First Letter Capitalization II](./leetcode/hard/3374.%20First%20Letter%20Capitalization%20II.sql)
 
 ## Contributing

leetcode/hard/601. Human Traffic of Stadium.sql

@@ -0,0 +1,50 @@
+/*
+Question 601. Human Traffic of Stadium
+Link: 
+
+Table: Stadium
+
++---------------+---------+
+| Column Name   | Type    |
++---------------+---------+
+| id            | int     |
+| visit_date    | date    |
+| people        | int     |
++---------------+---------+
+visit_date is the column with unique values for this table.
+Each row of this table contains the visit date and visit id to the stadium with the number of people during the visit.
+As the id increases, the date increases as well.
+ 
+
+Write a solution to display the records with three or more rows with consecutive id's, and the number of people is greater than or equal to 100 for each.
+
+Return the result table ordered by visit_date in ascending order.
+*/
+
+WITH more_than_100 AS (
+    SELECT 
+        s1.id,
+        s1.id - ROW_NUMBER() OVER (ORDER BY s1.id) AS c_id
+    FROM Stadium AS s1
+    WHERE s1.people >= 100
+),
+
+three_consecutive AS (
+    SELECT s2.c_id
+    FROM more_than_100 AS s2
+    GROUP BY s2.c_id
+    HAVING COUNT(s2.c_id) >= 3
+)
+
+SELECT 
+    s.id,
+    s.visit_date,
+    s.people
+FROM Stadium AS s
+INNER JOIN 
+    more_than_100 AS mt
+    ON s.id = mt.id
+WHERE mt.c_id IN (
+    SELECT tc.c_id
+    FROM three_consecutive AS tc
+)