Solution #500 (Python) - Daniel - 16/06/2025 - commit #4

Author: Daniel Nallapalli

Arrays & Strings/#500 - Keyboard Row - Easy/Solution.py

@@ -0,0 +1,16 @@
+class Solution(object):
+    def findWords(self, words):
+        """
+        :type words: List[str]
+        :rtype: List[str]
+        """
+        row1 = set("qwertyuiop")
+        row2 = set("asdfghjkl")
+        row3 = set("zxcvbnm")
+        
+        result = []
+        for word in words:
+            lower_word = set(word.lower())
+            if lower_word.issubset(row1) or lower_word.issubset(row2) or lower_word.issubset(row3):
+                result.append(word)
+        return result