2-mandatory-debug Done

Author: M-Abdoon

Sprint-2/2-mandatory-debug/0.js

@@ -1,6 +1,7 @@
 // Predict and explain first...
-
 // =============> write your prediction here
+// this code will use the declared function multiplay (a, b) to multiply two numbers, 10 and 32, and print the result to the console. 
+// However, the function can not be used to get the result because it does not return any value. Instead, it only logs the result to the console.
 
 function multiply(a, b) {
   console.log(a * b);
@@ -9,6 +10,13 @@ function multiply(a, b) {
 console.log(`The result of multiplying 10 and 32 is ${multiply(10, 32)}`);
 
 // =============> write your explanation here
+// the function does not return any value, it only prints the result to the console, so it can't be used to return anything, it will return "undefined".
 
 // Finally, correct the code to fix the problem
 //  =============> write your new code here
+
+function multiply(a, b) {
+  return a * b;
+}
+
+console.log(`The result of multiplying 10 and 32 is ${multiply(10, 32)}`);

Sprint-2/2-mandatory-debug/1.js

@@ -1,5 +1,7 @@
 // Predict and explain first...
 //  =============> write your prediction here
+// the function will throw an error because it does not return any value, the use of return without passing any value will cause an error.
+// also the last line of the function is unreachable because it comes after the return statement.
 
 function sum(a, b) {
   return;
@@ -9,5 +11,13 @@ function sum(a, b) {
 console.log(`The sum of 10 and 32 is ${sum(10, 32)}`);
 
 // =============> write your explanation here
+// The function will not return the expected sum because the return statement is not followed by any value.
+
 // Finally, correct the code to fix the problem
 //  =============> write your new code here
+
+function sum(a, b) {
+  return a + b;
+}
+
+console.log(`The sum of 10 and 32 is ${sum(10, 32)}`);

Sprint-2/2-mandatory-debug/2.js

@@ -1,7 +1,15 @@
 // Predict and explain first...
+// the code should display the last digit of any number passed to the function.
+// but there is an error which is the variable num is globally declared and has a value of 103.
+// the function does not take any parameters, and it takes the global variable num which is always 103.
+// that causes the code to always return 3 as 3 is the last digit of 103 which is the value of the global variable num.
 
 // Predict the output of the following code:
 // =============> Write your prediction here
+// since 3 is the last digit of 103, I think the output will be:
+// The last digit of 42 is 3
+// The last digit of 105 is 3
+// The last digit of 806 is 3
 
 const num = 103;
 
@@ -14,11 +22,29 @@ console.log(`The last digit of 105 is ${getLastDigit(105)}`);
 console.log(`The last digit of 806 is ${getLastDigit(806)}`);
 
 // Now run the code and compare the output to your prediction
+// The last digit of 42 is 3 ... the output is as I predicted.
+
 // =============> write the output here
+// The last digit of 42 is 3
+// The last digit of 105 is 3
+// The last digit of 806 is 3
+
 // Explain why the output is the way it is
 // =============> write your explanation here
+// because the function getLastDigit does not take any parameters, and it uses the global variable num which is always 103.
 // Finally, correct the code to fix the problem
 // =============> write your new code here
 
+// no need to declare the global variable num here. instead, we will pass it as a parameter to the function.
+function getLastDigit(num) {
+  return num.toString().slice(-1);
+}
+
+console.log(`The last digit of 42 is ${getLastDigit(42)}`);
+console.log(`The last digit of 105 is ${getLastDigit(105)}`);
+console.log(`The last digit of 806 is ${getLastDigit(806)}`);
+
+
 // This program should tell the user the last digit of each number.
 // Explain why getLastDigit is not working properly - correct the problem
+// because the function does not take the parameter so it will always use the variable num which is always 103.